    # How to print even numbers from 1 to 100 in JavaScript?

Write a JavaScript for loop that will iterate from 0 to 15. For each iteration, it will check if the current number is odd or even, and display a message to the screen.

Sample Output:
"0 is even"
"1 is odd"
"2 is even"
----------
----------

Calculate a Even Number: Even Numbers between 1 to 100: Calculate a Odd Number: Odd Numbers between 1 to 100: Sample Solution:-

HTML Code:

``````
<!DOCTYPE html>
<html>
<meta charset=utf-8 />
<title>For loop that will iterate from 0 to 15</title>
<body>

</body>
</html>
```
```

JavaScript Code:

``````
for (var x=0; x<=15; x++) {
if (x === 0) {
console.log(x +  " is even");
}
else if (x % 2 === 0) {
console.log(x + " is even");
}
else {
console.log(x + " is odd");
}
}
```
```

Sample Output:

```0 is even
1 is odd
2 is even
3 is odd
4 is even
5 is odd
6 is even
7 is odd
8 is even
9 is odd
10 is even
11 is odd
12 is even
13 is odd
14 is even
15 is odd
```

Flowchart: Live Demo:

See the Pen javascript-conditional-statements-and-loops-exercise-5 by w3resource (@w3resource) on CodePen.

In this section, we will create a Java program to display even numbers from 1 to 100. To learn the Java even number program, you must have the basic knowledge of Java for loop and if statement.

We can use different ways to display even numbers:

• Using Java for Loop
• Using nested-if Statement
• Using while Loop

## Using Java for Loop

In the following example, we have declared a variable named number and initialized it with 100 (the limit to print the even number). We have used a for loop that executes up to 100 times and for each iteration of i the if statement checks the number is even or not. After printing each even number, the value if i is increased by 1.

In order to check the number, we have divided the number by 2 if it does not leave any remainder, the number is even and the print statement prints that number.

DisplayEvenNumbersExample1.java

Output:

```List of even numbers from 1 to 100: 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 96 98 100
```

## Using nested-if Statement

The following program is slightly different from the above program because we have defined a method that contains the logic to check even number. Inside the method, we have used nested-if statement.

I want to print all even numbers between 10 and 40. But what’s wrong with my code?

code:

``````console.log("Print all even number between 10 and 40");
var num = 10;
while(num%2 == 0 && num < 40){
console.log(num);
num ++;
};
``````

When I run in on console it’s just print 10 First, to find an Even number it is very simple, divide the number by 2 if the remainder is zero then it’s an Even number.

Example if you give the start and end range from 10 to 20, the program has to print 10, 12, 14, 16, 18, 20. So let’s write a simple snippet now.

JavaScript

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for(i=10; i<=20; i++){

// let's divide the value by 2

// if the remainder is zero then it's an even number

if(i % 2 == 0){

console.log(i);

}

}

The above script should print the values in the console as expected.

Let’s write a dynamic script with HTML to get the start and end range from the user and print the output on the browser.

### How to show even number in JavaScript?

Example 1: Using if...else In the above program, number % 2 == 0 checks whether the number is even. If the remainder is 0, the number is even. In this case, 27 % 2 equals to 1. Hence, the number is odd.

### How to print all even numbers in JavaScript?

const isOdd = (n) => (n & 1) === 1; const num = [1,2,3,4,5,6,7,8,9]; console. log( `Odd numbers are \${ num. filter( n => isOdd(n))}` ); console. log( `Even numbers are \${ num..
const..
Arrow functions..
Bitwise AND (&).
Logical NOT (!).
Array. prototype. filter().

### How to sum 1 to 100 in JavaScript?

Example 1: Sum of Natural Numbers Using for Loop.
The value of sum is 0 initially..
Then, a for loop is used to iterate from i = 1 to 100 ..
In each iteration, i is added to sum and the value of i is increased by 1..
When i becomes 101, the test condition is false and sum will be equal to 0 + 1 + 2 + ... + 100 ..

### How do you print even numbers from 1 to 100?

Algorithm.
Start..
Start a loop for i = 1 to 100. Check if i is divisible by 2. If true, print the number. If false, increment the number.. 